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拙解, 不知道对不对

雪山飞鱼 2009-07-19 08:50:03 ( reads)

assume n=2k, then the probability of getting to the top of the ladder is
1/4 [(2k+1)/(4k)+2k/(4k)]+ 1/8 [(2k-1)/(4k)+(2k-2)/(4k)] +......+1/2^(k+1) [3/(4k)+2/(4k)]
for n large, ignoring the high order terms, the above is approximately 1/2-3/(8k)=1/2-3/(4n).

跟帖(5)

康MM

2009-07-20 16:10:44

飞鱼兄很厉害呀,在哪里做quant?

雪山飞鱼

2009-07-20 19:17:00

回复:飞鱼兄很厉害呀,在哪里做quant?

Commentate

2009-07-21 09:53:18

Can 康MM explain...

康MM

2009-07-22 09:24:57

回复:Can 康MM explain...

Commentate

2009-07-23 16:03:19

哇,这么费解,还面试题呢。