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Problem 6

botong 2009-07-24 10:32:52 ( reads)

通常第6题会比较难,今年的不一样?试着解,不对的话请指正。

There are n! different ways to arrange the jumps.
Given a point p between 0 and s = a_1+a_2+...a_n, it
has at most (n-1)! ways to reach. So the total ways to be matched is (n-1)(n-1)! which is less than n!. Also it
means there is at least one way that the grasshopper never lands on any point in M.











跟帖(6)

累死算了

2009-07-26 01:05:48

通常第六题不是最难的

botong

2009-07-26 09:25:21

通常第六题是最难的

dynamic

2009-07-26 22:14:34

有点问题吧

botong

2009-07-27 11:01:10

回复:有点问题吧

dynamic

2009-07-27 18:12:36

回复:回复:有点问题吧

botong

2009-07-28 10:22:54

回复:回复:回复:有点问题吧