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jinjing 2010-09-24 07:42:37 ( reads)

一对儿 5张一对儿中只有4种点不同,共有C(13,4)种,如AKQJ,各张有4色,AAKQJ,AKKQJ....AKQJJ有C(4,2)C(4,1)C(4,1)C(4,1)C(4,1)所以有C(13,4)C(4,2)C(4,1)C(4,1)C(4,1)C(4,1)/C(52,5)...
三对儿 5张3对儿中只有3种点不同:C(13,3)C(4,3)C(4,1)C(4,1)C(3,1)/C(52,5)...
3,2 P(13,2)C(4,3)*C(4,2)/C(52,5)=0.00140576

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