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Recursive formula : f(m+1)=7+f(m)-(m+1)*[(7+f(m))/(m+1)]

jinjing 2012-06-21 11:45:34 ( reads)

[...] ---interger value: [1/2]=0,[9/7]=1,...

跟帖(2)

jinjing

2012-06-21 12:04:10

m>7. f(m) : last number for m. f(1)=1,f(2)=2,...,f(7)=5, ...,

jinjing

2012-06-23 08:56:33

should be f(m+1)=7+f(m)-(m+1)*[(6+f(m))/(m+1)],f(25)=15.