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错在哪里?定理:所有的房子的颜色都是一样的。

wxcfan123 2012-08-22 18:28:33 ( reads)

Theorem. All horses are the same color.

Proof. We'll induct on the number of horses. Base case: 1 horse. Clearly with just 1 horse, all horses have the same color.

Now, for the inductive step: we'll show that if it is true for any group of N horses, that all have the same color, then it is true for any group of N+1 horses.

Well, given any set of N+1 horses, if you exclude the last horse, you get a set of N horses. By the inductive step these N horses all have the same color. But by excluding the first horse in the pack of N+1 horses, you can conclude that the last N horses also have the same color. Therefore all N+1 horses have the same color. QED.

Hmmn... clearly not all horses have the same color. So what's wrong with this proof by induction?

跟帖(12)

布衣之才

2012-08-22 19:01:27

先找出一条明显的错

wxcfan123

2012-08-22 19:42:17

haha...You are absolutely right.

jinjing

2012-08-23 05:25:21

没什么,用等价的概念就过去了.搞数学的,是粗心的细心人.

jinjing

2012-08-22 19:30:47

同色是比较概念,至少两个马.从2开始,如对,可推出所有马同色.

wxcfan123

2012-08-23 18:01:21

当然,任意两匹马同色等价于所有的马同色。问题是上面的证明错在哪?

jinjing

2012-08-23 20:00:24

错在同色的定义.一匹马同色,与其它马无关,这过程证明了每匹马与自己同色.

jinjing

2012-08-24 12:02:25

Real Math is here: f(hi1,i2,...,hit)=b,meaning t horses have b c

wxcfan123

2012-08-24 18:01:09

说说我的看法。这里的归纳推理的第二步有三个集合

cantorian

2012-08-25 18:57:23

谬在第二步。

wxcfan123

2012-08-25 20:41:07

这些集合并没有问题,它们是N+1匹马的两个子集。

cantorian

2012-08-25 22:19:22

这两个子集不是题目里的集。

发奖

2012-09-12 16:36:43

有趣