两个不同的条件： 1）考虑不同人的区别； 2）对所有人一视同仁。
1）考虑不同人的区别；
回复：N^n
对！谢谢！每个人都可选N个房中的任何一个，n个人就有N^n住法。
2）对所有人一视同仁。
回复：C(N+n-1,n)
对！此题有点挑战性。请解释下您的答案：C(N+n-1,n)
Blue too busy, I try...
Thanks for your try..., but hard to follow
解释：|OOO|OOOOOOOOOO|O||OOOOO|.....|OOO|||O|OOOOOOOOO|O|
回复：解释：|OOO|OOOOOOOOOO|O||OOOOO|.....|OOO|||O|OOOOOOOOO|O|
m people and n rooms: C(m+n-1,m), instead of C(m+n-1,n).
I'm sorry,I think n=N,at first.
sorry, not smart enough.
回复：sorry, not smart enough.
should be 1111---41,43,34,14 .
it seems i have understood you. you may have solved the problem
皆兄弟也
2010-06-14 08:57:201）考虑不同人的区别；